Question

Problem 6-16(b, c) The linkage shown below has $O_2A = 0.8$, $AB = 1.93$, $AC = 1.33$, and offset = 0.38 in. The crank angle in the position shown is $34.3^circ$ and angle $BAC = 38.6^circ$. Find $omega_3$, $V_A$, $V_B$, and $V_C$ for the position shown for $omega_2 = 15$ rad/sec (CCW) using instant center and analytical approaches.

          Problem 6-16(b, c)
The linkage shown below has $O_2A = 0.8$, $AB = 1.93$, $AC = 1.33$, and offset = 0.38 in. The
crank angle in the position shown is $34.3^circ$ and angle $BAC = 38.6^circ$. Find $omega_3$, $V_A$, $V_B$, and
$V_C$ for the position shown for $omega_2 = 15$ rad/sec (CCW) using instant center and analytical
approaches.

Problem 6-16(b, c)
The linkage shown below has O2A = 0.8, AB = 1.93, AC = 1.33, and offset = 0.38 in. The
crank angle in the position shown is 34.3^circ and angle BAC = 38.6^circ. Find omega3, VA, VB, and
VC for the position shown for omega2 = 15 rad/sec (CCW) using instant center and analytical
approaches.

Added by Patricia T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Stephen Zaffke

Step 1

We can use the formula for relative angular velocity: ω3 = ω2 * (AB / AC) * sin(BAC) Substituting the given values: ω3 = 15 rad/sec * (1.93 in / 1.33 in) * sin(38.6°) = 15.9 rad/sec Show more…

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Problem 6-16(b, c) The linkage shown below has O2A = 0.8, AB = 1.93, AC = 1.33, and offset = 0.38 in. The crank angle in the position shown is 34.3° and angle BAC = 38.6°. Find ω3, VA, VB, and VC for the position shown for ω2 = 15 rad/sec (CCW) using instant center and analytical approaches.