The liquour you are concentrating by evaporation is produced at 5kg/s coming at 300K. The steam is available saturated at 376K and its latent heat at the temperature is 2249 kJ/kg. The condensation temperature for the first effect and second effects are 359k and 325k which have their latent heat of steam as 2293kJ/kg and 2377 kJ/kg respectively. The evaporator is to evaporate 80% of the solution by mass. The overall coefficient of heat transfer for the first and second effect can be taken as 75 J/kg K and 30 J/kg K respectively. Assume the condensate leaves at condensation temperature and specify the number of 2m length tubes required if each has a 20 mm diameter. Also specify the economy of the reactor.
Added by Darnell C.
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Given that the liquor is produced at 5 kg/s and 80% of it is to be evaporated, the mass of liquor to be evaporated per second is: \[ \text{Mass to be evaporated} = 5 \, \text{kg/s} \times 0.80 = 4 \, \text{kg/s} \] Show more…
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