The load power for a buck-boost transformer that boosts the source by 30 V at a current of 50 A is ? kVA. a. 0.75 c. 1.5
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Step 1: The load power is given by the formula: $P = V \times I$ where $P$ is the power in watts, $V$ is the voltage in volts, and $I$ is the current in amperes. Show more…
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