00:01
Hi, i'm david and i'm here to have you answer your question.
00:03
In this question, we're given the density function given by fx equal to 0 .005, 20 minus x for the x between the 0 and the 20 equal to 0 otherwise.
00:22
Now in the part 1, we want to find the probability that the loss exists 16.
00:27
So means i want to find probability x greater than 16 by the formula for the continuous random variable, it's equal to integral, starting from 16 up to the 20, because then will be the equal for the x.
00:41
Now we're clicking you have 0 upon 0 0 ,0, 05, 20 minus x, the x.
00:48
Now to find this entire derivative, we get equal to the zon 0 0 05 times.
00:57
Times 20, get equal to the 0 .1 x, and then minus 0 .0 .05 x square over 2.
01:07
Evaluate from the 16 to the 20.
01:11
And if we do the calculation here, 20 times 0 .1, and then minus the 20 square, dividing by 2 times 0 .05, get equal to 1.
01:28
Minus for the 16 we have 16 square divided by two times 0 .0 .05 and then 0 .1 times 16 minus that get equal to the 0 .96 so we have one minus this here we got a 0 .0 .0 4 and that will be the part one for the quad 2 ,15 the cumulative distribution function...