The lowest energy triplet state in naphthalene (C10H8) is about 11,000 cm-1 below the lowest excited singlet electronic level at 77 K. Calculate the ratio of the populations in these two states.
Added by Justus F.
Step 1
The Boltzmann distribution gives the ratio of populations \( \frac{N_2}{N_1} \) between two states with energies \( E_2 \) and \( E_1 \) as: \[ \frac{N_2}{N_1} = e^{-\frac{E_2 - E_1}{kT}} \] where \( k \) is the Boltzmann constant and \( T \) is the temperature Show more…
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