The lowest frequency in the audible range is 20 Hz. What are the lengths of (a) the shortest open open tube and (b) the shortest open-closed tube needed to produce this frequency?
Added by Lawrence M.
Step 1
Given: Frequency (f) = 20 Hz, Speed of sound (v) = 343 m/s Using the formula for the fundamental frequency of an open tube: f = v / (2L) Substitute the values: 20 = 343 / (2L) Solve for L: L = 343 / (2*20) = 343 / 40 = 8.575 m Show more…
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