Question

The magnetic moment of the coil is ? = NIA, perpendicular to the plane of the coil, making an angle ? = 60° with the x axis as shown in the diagram. The direction of the vector B is along the x axis. (a) The torque on the dipole is given by the cross product ? = ? × B pointing down in the diagram and having a magnitude ? = NBAI sin ?, where A is the area of the rectangle, N is the number of coils in the rectangular loop, B is the magnitude of the magnetic field, I is the current, and ? is the angle between the magnetic ? moment and the magnetic field B. Substituting the given values, we have ? = ( )( T)( m²)( A)sin 60° = N · m.

          The magnetic moment of the coil is ? = NIA, perpendicular to the plane of the coil, making an angle ? = 60°
with the x axis as shown in the diagram. The direction of the vector B is along the x axis.

(a) The torque on the dipole is given by the cross product
? = ? × B
pointing down in the diagram and having a magnitude
? = NBAI sin ?,
where A is the area of the rectangle, N is the number of coils in the rectangular loop, B is the magnitude of the magnetic field, I is the current, and ? is the angle between the magnetic ? moment and the magnetic
field B. Substituting the given values, we have
? = (  )(  T)(  m²)(  A)sin 60°
=  N · m.

The magnetic moment of the coil is ? = NIA, perpendicular to the plane of the coil, making an angle ? = 60°
with the x axis as shown in the diagram. The direction of the vector B is along the x axis.

(a) The torque on the dipole is given by the cross product
? = ? × B
pointing down in the diagram and having a magnitude
? = NBAI sin ?,
where A is the area of the rectangle, N is the number of coils in the rectangular loop, B is the magnitude of the magnetic field, I is the current, and ? is the angle between the magnetic ? moment and the magnetic
field B. Substituting the given values, we have
? = ( )( T)( m²)( A)sin 60°
= N · m.

Added by Anne M.

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