The magnitude of the acceleration due to gravity on the surface of the Moon is g_{moon} = 1.62 m/s^2. An astronaut on the moon jumps with an initial speed of 7.1 m/s at an angle 33.1 degrees above the horizontal. How far from the starting point will the astronaut land? (in m) A: 21.41 B: 28.47 D: 50.36 E: 66.98 5pts Submit Answer Answer Submitted: Your final submission will be graded when the time limit is reached. Tries 1/99 Previous Tries In projectile motion questions like this one, time is the variable that links the horizontal and vertical motion. The motion in one of those directions can always be used to determine the "final" time, which you can plug into the expression for motion in the other direction. For this question, which equation did you use to solve for time? The horizontal, or the vertical? Why?
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1 m/s), \( \theta \) is the angle of launch (33.1 degrees), and \( g \) is the acceleration due to gravity on the Moon (1.62 m/s²). Show more…
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Problem 2. Kinematics: projectile motion A famous golf course designer is tasked with building a golf course on the moon. His reference for this project will be Tiger Woods, who can hit the ball 242 m on earth at an angle of 30° with an initial speed of 70 m/s. a) For how long is the golf ball airborne on earth? b) What is the maximum altitude of the golf ball on earth? (It occurs midway in its trajectory.) c) For how long is the golf ball airborne on the moon? d) How far would the ball travel on the moon? The acceleration due to gravity on earth is 9.8 m/s² and on the moon it is 1.6 m/s².
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The acceleration due to gravity on the Moon is $1.62 \mathrm{~m} / \mathrm{s}^{2}$ approximately a sixth of the value on Earth. For a given initial velocity $v_{0}$ and a given launch angle $\theta_{0}$, the ratio of the range of an ideal projectile on the Moon to the range of the same projectile on Earth, $R_{\text {Moon }} / R_{\text {Earth }},$ will be approximately a) 6 . b) 3. c) 12 . d) 5. e) 1 .
Timothy J.
Lunar Projectile Motion A rock thrown vertically upward from the surface of the moon at a velocity of 24 $\mathrm{m} / \mathrm{sec}$ (about 86 $\mathrm{km} / \mathrm{h} )$ reaches a height of $s=24 t-0.8 t^{2}$ meters in $t$ seconds. (a) Find the rock's velocity and acceleration as functions of time. (The acceleration in this case is the acceleration of gravity on the moon.) (b) How long did it take the rock to reach its highest point? (c) How high did the rock go? (d) When did the rock reach half its maximum height? (e) How long was the rock aloft?
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