The escape velocity \( v_e \) from a celestial body is given by:
\[ v_e = \sqrt{\frac{2GM}{R}} \]
where:
- \( G \) is the gravitational constant (\( 6.67430 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2} \)),
- \( M \) is the mass of the celestial
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