The mass of object 1 is $m_1 = 52$ kg, the distance between the two objects is $d = 1$ meter. The center of mass (for the two objects) is located at C, $x_1 = 0.55$ meter. Calculate $m_2$ (in kg).
Added by Denise W.
Close
Step 1
Step 1: The center of mass $x_c$ of a two-object system is given by: $x_c = \frac{m_1x_1 + m_2x_2}{m_1 + m_2}$ where $x_1$ and $x_2$ are the positions of the objects $m_1$ and $m_2$ respectively, relative to some origin. Show more…
Show all steps
Your feedback will help us improve your experience
Prabhu Ramji and 101 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Prabhu R.
Four objects are situated along the $y$ axis as follows: a $2.00-\mathrm{kg}$ object is at $+3.00 \mathrm{m},$ a $3.00-\mathrm{kg}$ object is at $+2.50 \mathrm{m},$ a 2.50 -kg object is at the origin, and a $4.00-\mathrm{kg}$ object is at $-0.500 \mathrm{m} .$ Where is the center of mass of these objects?
Four objects are situated along the $y$ axis as follows: $\mathrm{A}$ $2.00-\mathrm{kg}$ object is at $+3.00 \mathrm{~m}$, a $3.00-\mathrm{kg}$ object is at $+2.50 \mathrm{~m}$, a $2.50-\mathrm{kg}$ object is at the origin, and a $4.00-\mathrm{kg}$ object is at $-0.500 \mathrm{~m} .$ Where is the center of mass of these objects?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD