00:01
Hello students.
00:02
So in this question, we are given with the, this whole spectra of tertiary butyl bromide with the molecular weight of 137.
00:12
Okay.
00:13
The molecular weight of 137.
00:15
And you have been asked to draw the structures of all the fragments that are given in these signals.
00:20
Okay.
00:20
These are the signals.
00:21
Some peaks we have.
00:23
Right.
00:23
And you have to draw the structure of the fragment according to these peaks, okay, which are given.
00:28
So let's get started to our question.
00:30
So if we have a structure, if we have a structure which is tertiary, which is c4 h9, br, so it is actually what, it is actually tertiary butyl.
00:49
It is what tertiary butile and if i have to draw the structure, it will be tertiary butyl bromide structure will be like this.
00:56
Tertiary because one carbon is attached with three other carbons, right? so now if i have to draw the fragments, if i have to draw the fragments, so fragments will be, so here if i am drawing the fragments, so first fragment, if corresponding to, i'll draw these corresponding to their peaks that we have over here, right, if first fragment is at the peak of 57, at the peak of 57, we have it as c4h9 as a positive charge.
01:39
Okay, so c4 h9 will be something i draw the structure it will be c4, okay, this h3, here ch3 and here we have ch3 and this will be the structure.
01:54
All right.
01:55
So this is the structure for the first one, which i have picked and the second, if we talk about the second signal, we have over here now, if you see the structure over here.
02:07
See, i'll first write down the all the values of 57.
02:10
We had...