00:01
So in this question, you are given two blocks on a grant, right? and this friction between this block and the ground with a friction coefficient, which i call the m1 equals 0 .25.
00:15
And similar, this friction between this block and the service, which has a friction coefficient that i call mure 2 equal to 0 .4.
00:25
And then you pull this to block.
00:26
And this box are also connected by, by a strain or something, right, which makes your anger with a horizontal direction to be 30 degrees.
00:38
I call this angle to be c -tile, right? and of course, there would be a tension within this rope, right, with this strain of rope or something.
00:46
And then you pour these two blocks with force p, and of course, you need a minimum force so that you can actually move them to overcome the friction, right? so basically, the minimum force is the maximum static friction.
01:00
Can work out, you can get.
01:04
To work out there, we need to really find the normal reaction force on this surface and the normal fraction force on the surface, right? so let's analyze these blocks one by one.
01:15
You look at this block, you will have a normal reaction for a screen upward, which i call it n1, and you have a weight, right, w1.
01:26
And of course, you have a force here, which i move to here, makes an angle, which i call it t.
01:31
T, this is going in upward direction.
01:35
And now you look at this object, it also has a weight, which is w2, given in the parents, right? then you have a normal reaction force n2.
01:48
And then, of course, you also have for force t, which is going actually a little bit downward, right? so you see that you can, you know, you can using the equation the brim of forces you can find a few equations, right? and first you see that the, first you see that the, you know, w, first you see the n1.
02:16
Let's look at n1 first.
02:18
So n1 must be equal to w1 minus t.
02:24
You know, you have to decompose the t...