00:01
In this question, i'm going to let x follows the binomial distribution in this question with n the number of trials and p probability of success in a single trial.
00:14
And we are given that the mean is 3 and the variance is 2.
00:25
So mean is expectation of x and for binomial distribution that will be n times p.
00:32
And this is 3, so equation 1.
00:34
Now variance of x for a binomial distribution will be np times 1 minus p and this will be 2.
00:44
So this is equation 2.
00:46
Now i'm going to sub this np with 3.
00:53
So sub 1 into 2, i will have np is 3 times 1 minus p is equals to 2.
01:07
So 1 minus p is 2 third and so 1 minus 2 third is equals to p and therefore p is 1 third.
01:16
So i'm going to sub this into equation 1.
01:25
I have n times 1 third, that's my p is equals to 3.
01:30
So n is 9.
01:32
So therefore x follows the binomial distribution n is 9, p is 1 third...