00:01
Hello students, welcome.
00:02
We have a question here and here it is given that the mean for sample of 14 colleges is given here as 38 .0 and samples n will be equal to 14 private colleges so this will be equal to 14 and the standard deviation will be equal to $6 ,000.
00:30
So here we need to find the as the half of the this is given here for h .o and alpha is here 0 .01 level of significance.
00:43
So let's start solving this question over.
00:47
So first of all we have to find the value for you.
00:52
So here into the solution of this question.
00:57
The sample standard deviation is given here.
00:59
So given population is normal, normal but the population is standard deviation.
01:13
Population standard deviation is unknown is unknown so therefore we will take that as ux t test for we will use unknown therefore we use we use t test for testing the mean so here h -4, the null hypothesis to you will be equal to 3390.
02:07
And alternative hypothesis, h -a or h -1, will be for mu, does not equal to 339 -0.
02:22
Therefore, the t test for this will be x bar minus mu x divided by s by square root of n.
02:35
And this will be similar to t n minus 1, comma, alpha, by...