00:01
In this question we're given the mean value of the data set, which is denoted by mu, that was given as 2 .91, this is the mean, the population mean, and the standard deviation.
00:11
So the standard deviation for the population denoted by sigma here, which was given as 3 .88, so we have to find the z -score.
00:19
So let me define the random variable x, and we need to find the z -score.
00:24
First of all, remember the conversion formula from x to z -score, so the z is equal to, which is x minus mu over standard deviation.
00:32
So for x is equal to 5 .80, the z -score is equal to, instead of x on the formula, i'm going to put 5 .80 minus the mean, 2 .91, and divide it by the standard deviation, 3 .88...