00:01
Hi everyone.
00:01
So in this question, what is the molarity of the nitric acid solution? so we are given the reaction in which barium hydroxide react with nitric acid to form barium nitrate plus water.
00:16
So first we have to balance this equation.
00:19
So i'm using the stochometric coefficient two in nitric acid and the stochometric coefficient two in water so that the equation is balanced.
00:28
And in this equation, 1 mole of barium hydroxide react with the 2 mol of nitric acid and it will produce 1 mole of berym nitrate and 2 mole of water.
00:41
Now what we are given in the question, normality of barium hydroxide and volume of barium hydroxide solution that is given in the question.
00:52
So with the help of this data we can first find out the moles of berym hydroxide, then we can apply the concept of the stochometry to find the molecule.
01:00
Of nitric acid.
01:03
So molts of barium hydroxide.
01:05
So basically volume we can convert into liter, basically one liter that is 1 ,000 millilitres.
01:11
So apply this conversion...