00:01
So, the first part of the question is to determine the ?h and the ?s for the following reaction.
00:09
So, here the let us first find out the k which is the equilibrium constant of the rnas.
00:17
So, here we will be using this formula where the k which is the equilibrium constant is equal to rna is denatured divided by the rna is active.
00:30
So, here for different temperature so for t1 which is equal to 5 degree celsius or by converting it into kelvin it is equal to 278 kelvin.
00:47
So, let us put the value so here the k1 is thus equal to so here the rna is denatured at this temperature is 0 .005 divided by rna is active which is 0 .995.
01:03
So, here it is equal to 0 .005025 so this is k1.
01:08
Now we will calculate for temperature t2 which is equal to 100 degree celsius or we can say it is equal to 373 kelvin.
01:18
So, here the k2 is equal to 1 divided by 1 and it is equal to 1.
01:24
So, this is the k1 and k2 value.
01:27
Now we can use the venthoff equation to determine the enthalpy change.
01:32
So to determine the enthalpy change and the entropy change for the following folding.
01:38
So, we will be using this formula where so by using this venthoff equation we can calculate the ?h by putting the value.
01:45
So, here the r is the universal gas constant and it is equal to 8 .314 joule per mole per kelvin.
01:57
So, now let us put the value over here.
01:59
So, by putting the value and calculating from here we will calculate the ?h value.
02:05
So, here the ?h is thus equal to minus of 1 .71 into 10 raised to the power 5 joule per mole.
02:17
So, this is the ?h value.
02:19
Now we will calculate for the ?s value...