00:01
In this problem, the near point of a naked eye is 32 centimeters when an object is placed at a near point and viewed by the naked eye.
00:13
It has an angular size of 0 .6 radium.
00:20
A magnifying glass has a focal length of 16 centimeters and held next to the eye.
00:32
The enlarged image that is seen is located 64 centimeters from the magnifying class.
00:46
Right.
00:47
So now we are asked to determine the angular size of the image.
00:53
Right.
00:54
So here what all things are given to us is near point of naked eye is 32 centimeters.
01:01
Okay.
01:04
So here is 32 centimeters.
01:10
Is for near point, right? so, what we can say is let us represent it as n, right? this is near point.
01:18
Now, angular size of the object, when it is placed at the near point, was 0 .060, right? 0 .060 radiance.
01:36
Right.
01:36
So this is what? this is, let us represent it as alpha, right? so now magnifying glass has focal length f, let us say.
01:45
So this is what? this is 16 centimeters.
01:48
And enlarged image is located at d, right? which is 64 centimeters.
01:55
All right.
01:56
So now magnification of magnifying glass that is represented as m, which is actually equals to alpha dash upon alpha, right? so alpha dash is what? alpha dash is angular size with the magnifying glass right so alpha dash is angular size with the magnifying glass right and alpha is angular size without magnifying glass right which is actually given to us which is 0 .060 radiance okay now we have to just use the formula right so what is the formula for magnification...