00:01
Hello students, let's begin with this question.
00:02
In the first part of this question we have to write down the balanced reaction between the hcl and the sodium bicarbonate that is nahco3.
00:16
So, the balanced equation is 1 mole of hcl, it will react with the 1 mole of nahco3 and this will result to the formation of the nacl, 1 mole of nacl plus 1 mole of water and release the carbon dioxide gas.
00:38
So, this is the balanced equation as number of atoms on the product side is equals to number of atoms on the reactant side.
00:44
Now, in the second part of this question, in this question mass of sodium bicarbonate is given which is equals to 0 .47 gram and we have to find out the moles of the hcl.
01:00
So, firstly this mass is converted into the moles by using the formula that moles is equals to given mass upon the molar mass of the substance.
01:11
So, now from here the moles of nahco3 is equals to its mass is 0 .47 gram and molar mass of sodium bicarbonate is equals to 84 .007 gram per mole.
01:29
So, from here the moles of sodium bicarbonate is equals to this is equals to 0 .0055 moles...