Question

The normal boiling point of acetone [(CH3)2CO; MW 58.08 g/mol] is 56.1°C, and its molar enthalpy of vaporization is 29.1 kJ/mol. What is the molar entropy of vaporization of 30.3 g of acetone? What is the total entropy of vaporization of 30.3 g of acetone?

Name: the normal boiling point of acetone ch32co mw 5808 gmol is 561c and its molar enthalpy of vaporization is 291 kjmol what is the molar entropy of vaporization of 303 g of acetone what is the 12857
Uploaded: 2022-02-05T16:13:06-08:00
Duration: 2 min 45 s
Channel: David Collins
Description: the normal boiling point of acetone ch32co mw 5808 gmol is 561c and its molar enthalpy of vaporization is 291 kjmol what is the molar entropy of vaporization of 303 g of acetone what is the 12857

          The normal boiling point of acetone [(CH3)2CO; MW 58.08 g/mol] is 56.1°C, and its molar enthalpy of vaporization is 29.1 kJ/mol. What is the molar entropy of vaporization of 30.3 g of acetone? What is the total entropy of vaporization of 30.3 g of acetone?

Added by Sarah M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

02/05/2022

Step 1

We can do this using the formula: Number of moles = mass / molar mass = 30.3 g / 58.08 g/mol = 0.521 moles The molar entropy of vaporization (ΔSvap) can be calculated using the formula: ΔSvap = ΔHvap / T where ΔHvap is the molar enthalpy of vaporization and Show more…

Show all steps

Thanks for your feedback!

The normal boiling point of acetone [(CH3)2CO; MW 58.08 g/mol] is 56.1°C, and its molar enthalpy of vaporization is 29.1 kJ/mol. What is the molar entropy of vaporization of 30.3 g of acetone? What is the total entropy of vaporization of 30.3 g of acetone?