The normal boiling point of benzene is 80.1°C. What is its enthalpy of vaporization if the vapor pressure at 26.1°C is 100 torr?
Added by Dustin S.
Step 1
ĪT = Tā - Tā = 26.1°C - 80.1°C = -54°C Note: The temperature difference is negative because we are going from a lower temperature to a higher temperature. Show moreā¦
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