00:01
Hi, i'm david and i'm here to help you answer your question.
00:03
Now let me bring up your question here.
00:06
In the question here we are going to discuss about the normal distribution.
00:10
Let me remind you that if we have the x that follows by the normal, with the mean and the standard division and then the x minus the mean of a standard division, we will obtain the standard normal.
00:22
In the question here we have the x will follow by the normal, when the mean equal to the 6 .8 and the standard division equal to the 1 .6.
00:33
Now let me try to draw the graph on the density on the normal.
00:37
It will have a bell curve.
00:39
The middle value will be the mean will be the 6 .8, and this will be something on the left and something on the right.
00:50
There will be, we turn the 6 .8 and then we minus 1, standard division 1 .6, and then get equal to the 5 .2.
00:59
And for this value here we turn the 6 .8, we plus with the 1 .6 equal to the 8 .4.
01:09
And now we want to express the event that the student chosen has the score of the 8 .4 or lower in terms of the x...