The number of accidents in a production facility has a Poisson distribution with a mean of 2.6 per month. a. For a given month, what is the probability there will be fewer than 2 accidents? b. For a given month, what is the probability there will be more than 3 accidents?
Added by Jason A.
Step 1
6 in this case. P(X < 2) = e^(-2.6) * (2.6^0/0!) + e^(-2.6) * (2.6^1/1!) P(X < 2) = 0.3031 + 0.7879 P(X < 2) = 1.091 However, probabilities cannot be greater than 1, so we know that this answer is incorrect. The reason for this is that we used the wrong formula. Show more…
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