The number of bacteria N at a certain time t is given by N = 100e^(t/10), when there are 100 bacteria at time t = 0 hours. Find how many hours t it takes for the bacteria to double (that is, increase from 100 to 200 bacteria). [Use either ln(2) ≈ 0.7 to approximate your answer as appropriate.]
Added by Matthew N.
Step 1
Step 1: Set the function equal to 200 (double the initial value of 100): \[200 = 100e^{t/10}\] Show more…
Show all steps
Close
Your feedback will help us improve your experience
Kathleen Carty and 81 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Assume that the total number N(t) (in millions) of bacteria present in a culture at a certain time t (in hours) is given by the formula: N=3t(t-5t)+10. The rate of change of the number of bacteria at the second hour.
Taru H.
Bacteria Growth The number N of bacteria in culture is modeled by N= 250e^kt where t is the time in hours. If N = 280 when t= 10, estimate the time required for the population to double in size.
Allison K.
The number of bacteria in a culture can be modeled by the function N(t) = 2000 (1 + 2t / (t^2 + 100)), where t is measured in hours. a) Find the rate of change of the number of bacteria. N'(t) =
Sri K.
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD