The number of combinations of n items taken 3 at a time is 92n. Find the value of the constant n.
Added by Matthew W.
Step 1
First, we know that the number of combinations of n items taken 3 at a time can be represented by the binomial coefficient: $$\binom{n}{3} = \frac{n!}{3!(n-3)!}$$ We are given that this is equal to 92n: $$\frac{n!}{3!(n-3)!} = 92n$$ Now, we can simplify the Show more…
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