00:01
So in this problem we're told that a counselor that's new to a college was told that the average credit students register for each semester is 12 .4 with a standard deviation of 1 .8 credits.
00:11
Let's jot that down.
00:13
Our mean is 12 .4 and our standard deviation is 1 .8.
00:18
It says the counselor takes a random sample of 40 students and collects the number of credits that they register.
00:23
So our sample size here is 40.
00:26
And we're asked to first find the mean and the standard deviation of the sampling distribution.
00:31
So the mean of the sampling distribution is equal to the population mean, which we were told is 12 .4.
00:38
So there's no more calculating to be done there.
00:42
But the standard deviation for the sampling distribution is equal to the population standard deviation divided by the square root of the sample size n.
00:50
So for this we'll have to do a little bit more calculating.
00:53
But it's not too bad because all we have to do is divide our population standard deviation, 1 .8, by the square root of our sample size n, which is 40.
01:03
Now when we calculate that, we're onto two decimal places, we get 0 .28 as our standard deviation for the sample.
01:10
Now that we have those two values, we're asked to find the probability that within this sample of 40 students the average credits registered will be more than 13...