The number of dry cells, each of e.m.f. 1.5 volt and internal resistance 0.5 ohm that must be joined in series with a resistance of 20 ohm so as to send a current of 0.6 ampere through the circuit is (a) 2 (b) 8 (c) 10 (d) 12
Added by Yash G.
Step 1
Given: Internal resistance of each dry cell, r = 0.5 ohm Resistance of each dry cell, R = 20 ohm Number of dry cells = n Total resistance, R_total = n * (R + r) ** Show more…
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