Question

The number of solutions to $x_1 + x_2 + x_3 + x_4 = 20$ where $x_1, x_2, x_3, x_4$ are positive integers is: ?$\binom{19}{3}$ ?$\binom{24}{4}$ ?$\binom{23}{3}$ ?$20^4$

          The number of solutions to $x_1 + x_2 + x_3 + x_4 = 20$ where $x_1, x_2, x_3, x_4$ are positive integers is:
?$\binom{19}{3}$
?$\binom{24}{4}$
?$\binom{23}{3}$
?$20^4$

The number of solutions to x1 + x2 + x3 + x4 = 20 where x1, x2, x3, x4 are positive integers is:
?193
?244
?233
?20^4

Added by Teresa F.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Adi S

05/29/2023

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The number of solutions to x_(1)+x_(2)+x_(3)+x_(4)=20 where x_(1),x_(2),x_(3),x_(4) are positive integers is: ((19)/(3)) ((24)/(4)) ((23)/(3)) 20^(4) The number of solutions to + 2 + 3 +4=20 where 1,2,3,4 are positive integers is: 0( O (24) (3) 204