The number of traffic accidents per week at intersection Q has a Poisson distribution with mean 2. The number of traffic accidents per week at intersection R has a Poisson distribution with mean 1.5. Let A be the probability that the number of accidents at intersection Q exceeds its mean. Let B be the corresponding probability for intersection R. Calculate B-A
Added by James P.
Step 1
Given that the mean number of accidents at intersection Q is 2, we need to find P(NQ > 2). Using the Poisson distribution formula, we have P(NQ > 2) = 1 - P(NQ ≤ 2). P(NQ ≤ 2) = e^(-2) * (2^0 / 0!) + e^(-2) * (2^1 / 1!) + e^(-2) * (2^2 / 2!) = 0.6767. Therefore, Show more…
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