00:01
For testing the chi -square test of independence, the null hypothesis is that the two attributes given are independent.
00:16
So this is the null hypothesis and for this, a contingency table will be given as the observed frequencies are considered.
00:23
And for this, that means for this null hypothesis, the expected frequencies are calculated using the formula that for each cell, it is calculated as a row total of that cell into column total of that cell divided by the grand total.
00:50
That is the total number of the sample size which are surveyed.
00:56
Now it is given we can write this as there are t columns are there which is notated as abc and two rows are available such as 192 and the row totals, surveyed frequencies are there.
01:11
So we can just write the row totals and the column totals here and the grand total is 250, the column total here is 90, here 160, here 60 and this is 85, here 105.
01:36
Now considering this cell, here the row total is 90 and the column total is 60.
01:42
Here the column total, this is the row total corresponding to this cell and the grand total is 250...