The owner of a fish market determined that the average weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pounds. Assuming the weight of catfish are normally distributed What is the probability that a randomly selected catfish have weight between 3 and 5 pounds? Above what weight (in pounds) do 89.80% of the weights occur?
Added by Domingo R.
Step 1
First, we need to find the z-scores for the given weights (3 and 5 pounds) using the formula: z = (x - μ) / σ where x is the weight, μ is the mean (3.2 pounds), and σ is the standard deviation (0.8 pounds). Show more…
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