00:01
The reaction that we're considering is 4 moles of ammonia, nh3, reacts with 3 moles of o2, to produce 2 moles of n2, and 6 moles of h2o.
00:18
So we could write the, i believe their equivalent rate expression, is for the rate of the reaction.
00:24
The rate of the reaction is going to be equal to negative 1 over the coefficient for each reactant, multiplied by the change in concentration of each reactant, the negative because the concentrations are changing or decreasing, and we can't have a negative rate.
00:43
So the negative here cancels the negative created here.
00:48
That will also be equal to negative 1 over the coefficient for the second reactant, multiplied by its change in concentration over change in time, which will be equal to positive one over the coefficient for each product, positive because these concentrations are now increasing.
01:16
So if we know the rate of change of h2o, we can determine the rate of formation of n2...