Question

The oxidation of the sugar glucose, C6H12O6, is described by the following equation: C6H12O6(s) + 6O2(g) ⟶ 6CO2(g) + 6H2O(l) ΔH = -2816 kJ The metabolism of glucose gives the same products, although the glucose reacts with oxygen in a series of steps in the body. How much heat in kilojoules can be produced by the metabolism of 1.0 g of glucose?

Name: the oxidation of the sugar glucose c6h12o6 is described by the following equation c6h12o6s6o2g6co2g6h2olh2816kj the metabolism of glucose gives the same products although the glucose reacts 58647
Uploaded: 2022-02-25T19:15:26-08:00
Duration: 52 s
Channel: Ronald Prasad
Description: the oxidation of the sugar glucose c6h12o6 is described by the following equation c6h12o6s6o2g6co2g6h2olh2816kj the metabolism of glucose gives the same products although the glucose reacts 58647

          The oxidation of the sugar glucose, C6H12O6, is described by the following equation:
C6H12O6(s) + 6O2(g) ⟶ 6CO2(g) + 6H2O(l) ΔH = -2816 kJ
The metabolism of glucose gives the same products, although the glucose reacts with oxygen in a series of steps in the body. How much heat in kilojoules can be produced by the metabolism of 1.0 g of glucose?

Added by Angela K.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ronald Prasad

02/25/2022

Step 1

16 g/mol. Then, we can calculate the number of moles of glucose in 1.0 g by dividing the mass of glucose by its molar mass. 1.0 g / 180.16 g/mol = 0.00555 mol The equation tells us that one mole of glucose produces -2816 kJ of heat. Show more…

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The oxidation of the sugar glucose, C6H12O6, is described by the following equation: C6H12O6(s) + 6O2(g) ⟶ 6CO2(g) + 6H2O(l) ΔH = -2816 kJ The metabolism of glucose gives the same products, although the glucose reacts with oxygen in a series of steps in the body. How much heat in kilojoules can be produced by the metabolism of 1.0 g of glucose?