00:01
Hi, in this question we are given with 4 equations and we are asked to balance them.
00:05
The first equation is here, n2 plus o2 gives no.
00:10
We have nitrogen atoms and oxygen atom on the both side.
00:14
Here nitrogen is 2 in number and oxygen is also 2.
00:18
Here nitrogen is 1 and oxygen is also 1.
00:22
Therefore, if we put 2 coefficient in front of no, then we will be having 2 nitrogen atom and 2 oxygen atom.
00:31
Hence the reaction is balanced now.
00:33
We can rewrite it as n2 plus o2 gives 2no.
00:42
Now the second equation we have is no plus o2 gives no2.
00:48
Here we have nitrogen and oxygen atoms.
00:51
Nitrogen is 1 in number and oxygen is 3.
00:56
Here nitrogen is 1 and oxygen is 2 in number.
00:59
We can see nitrogen is balanced but oxygen is not balanced.
01:04
We have odd number in reactant and even number in product.
01:09
Therefore, if we put 2 coefficient in front of no, then here we will be having 2 nitrogen atom and now we can see we have 2 plus 2 that is 4 oxygen atoms.
01:23
But here we can see we have 1 nitrogen and 2 oxygen.
01:28
Hence we can put 2 coefficient in front of here also.
01:31
Now we have 2 nitrogen and 4 oxygen atom.
01:35
This is the balanced equation.
01:37
We can rewrite it 2no plus o2 gives 2no2...