The path of a large stone fired from a torsion catapult can be modeled by y = -0.0054x^2 + 1.145x, where x is the distance the stone traveled (in yards) and y is the height of the stone (in yards).
Added by Morgan D.
Step 1
0054 and b = 1.145. x = -1.145/(2*(-0.0054)) = 105.8 So the vertex is at (105.8, y), where y is the maximum height of the stone. Show more…
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