The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.7 days and a standard deviation of 2.1 days. What is the probability of spending more than 2 days in recovery? (Round your answer to four decimal places.)
Added by Jostyn S.
Step 1
Given: Mean (Ī¼) = 5.7 days Standard Deviation (Ļ) = 2.1 days X = 2 days Z = (X - Ī¼) / Ļ Z = (2 - 5.7) / 2.1 Z = -3.7 / 2.1 Z = -1.76 Show moreā¦
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