The period of the function \begin{equation*} x(t) = \sin(2\pi t) \end{equation*}
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The angular frequency, ω, is the coefficient of t in the function, which in this case is 2Ï€. The period, T, is the time it takes for the function to complete one full cycle. The formula for the period is T = 2Ï€/ω. Substituting ω = 2Ï€, we get T = Show more…
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The time average of some function $f(t)$ taken over an interval $T$ is given by $$\langle f(t)\rangle_{\mathrm{T}}=\frac{1}{T} \int_{t}^{t+T} f\left(t^{\prime}\right) d t^{\prime}$$ where $t^{\prime}$ is just a dummy variable. If $\tau=2 \pi / \omega$ is the period of a harmonic function, show that $\overrightarrow{\mathbf{r}}$$$\begin{array}{l}\left\langle\sin ^{2}(\overrightarrow{\mathbf{k}} \cdot \overrightarrow{\mathbf{r}}-\omega t)\right\rangle=\frac{1}{2} \\\left\langle\cos ^{2}(\overrightarrow{\mathbf{k}} \cdot \overrightarrow{\mathbf{r}}-\omega t)\right\rangle=\frac{1}{2}\end{array}$$ and$$\langle\sin (\overrightarrow{\mathbf{k}} \cdot \overrightarrow{\mathbf{r}}-\omega t) \cos (\overrightarrow{\mathbf{k}} \cdot \overrightarrow{\mathbf{r}}\omega t)\rangle=0$$when $T=\tau$ and when $T>>\tau$.
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