00:01
Hello, in this problem, the given data, ph is equal to 10 .1 2.
00:15
And the concentration of solution is equal to 0 .30 molar.
00:30
We have to find out the value of kb.
00:40
P .h is equal to 14 minus ph.
00:47
Put the value of ph, the poh is equal to 14 minus 10 .1 .2.
01:00
So the value of poh is equals to 3 .88.
01:09
Now the formula of poh is equals to 1 by 2 into pkb minus low of concentration of c.
01:27
This is the formula of poh.
01:32
The values 3 .88 is equal to 1 by 2 into pkb minus log of concentration of c is 0 .30 molar.
01:57
Now 3 .88 multiply by that is equals to pkb minus log of 0 .30.
02:10
This will be equals to 7 .76 is equal to pkb minus log of concentration of 0c 0 .30.
02:27
Now the value of log of 0 .3 is equal to minus 0 .52...