The pKa of hypochlorous acid (HOCl) is 7.53. If you prepare a 0.05 M solution of HOCl(aq), a) What percent of the HOCl will dissociate? b) What will the pH be?
Added by James K.
Step 1
pKa = -log(Ka) Ka = 10^(-pKa) = 10^(-7.53) Now, let's set up an ICE table for the dissociation of HOCl: HOCl(aq) ↔ H+(aq) + OCl^-(aq) Initial: 0.05 M 0 M 0 M Change: -x M +x M +x M Final: 0.05-x M x M Show more…
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