00:01
All right, so we have a loop of wire, and it has dimensions of 8 centimeters by 5 centimeters, and it's subject to a magnetic field that is parallel to the loop.
00:13
And we want to calculate what's the torque on this loop if the current through the loop is 6 .2 amps, and the magnetic field strength is 0 .19 tesla.
00:24
So the torque on a loop or any object, any object of the magnetic moment, it's going to be like mu cross b, where mu is the magnetic moment.
00:35
So this comes up to like mu times b times the sign of the angle between those two vectors.
00:41
Now in this case, the magnetic moment of the loop points outwards.
00:45
So the sign of the angle is already maximized, right? it's a 90 degree angle.
00:49
So really, the torque is just going to be the magnetic moment of the loop times the magnetic field strength and the magnetic moment of the loop is going to be the current in the loop times the area of the loop and so that should come out to about 0 .0248 meters squared times an ampere that's our magnetic moment and so that means our torque is going to be 0 .048 meters squared times an ampere times 0 .19 tesla and so that gives us a torque of about 4 .712 times 10 .10...