Question

6. The plane ? has the vector equation $\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 7 \\ 9 \\ 1 \end{bmatrix} + s \begin{bmatrix} 1 \\ 2 \\ 1 \end{bmatrix} + t \begin{bmatrix} 2 \\ 3 \\ 1 \end{bmatrix}$. A vector perpendicular to this plane is \\ (A) $[1, -1, 2]^T$ (B) $[1, -1, 1]^T$ (C) $[7, 9, 1]^T$ (D) $[1, 0, -2]^T$ (E) $[-1, 7, -9]^T$

          6. The plane ? has the vector equation $\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 7 \\ 9 \\ 1 \end{bmatrix} + s \begin{bmatrix} 1 \\ 2 \\ 1 \end{bmatrix} + t \begin{bmatrix} 2 \\ 3 \\ 1 \end{bmatrix}$. A vector perpendicular to this plane is \\
(A) $[1, -1, 2]^T$ (B) $[1, -1, 1]^T$ (C) $[7, 9, 1]^T$ (D) $[1, 0, -2]^T$ (E) $[-1, 7, -9]^T$

6. The plane ? has the vector equation < b m a t r i x >
=
< b m a t r i x >
+ s
< b m a t r i x >
+ t
< b m a t r i x >. A vector perpendicular to this plane is

(A) [1, -1, 2]^T (B) [1, -1, 1]^T (C) [7, 9, 1]^T (D) [1, 0, -2]^T (E) [-1, 7, -9]^T

Added by Mary P.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Adi S

10/27/2023

Step 1

Step 1: The vector equation of the plane \pi is given by [[x],[y],[z]]=[[7],[9],[1]]+s[[1],[2],[1]]+t[[2],[3],[1]]. Show more…

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The plane pi has the vector equation [[x],[y],[z]]=[[7],[9],[1]]+s[[1],[2],[1]]+t[[2],[3],[1]]. A vector perpen- dicular to this plane is (A) [1,-1,2]^(T) (B) [1,-1,1]^(T) (C) [7,9,1]^(T) (D) [1,0,-2]^(T) (E) [-1,7,-9]^(T) a 6. The plane T has the vector equation y 9 +s 2 +t 3 .A vector perpen- 1 dicular to this plane is (A) [1, -1, 2]T B [1, -1, 1]T (C) [7,9,1]T (D) [1, 0, -2]T (E) [-1,7,-9]T