FA = 8 kN A ? 40° B FB = 6 kN The plate is subjected to the two forces at A and B as shown. If theta is 60°, determine the magnitude of the resultant of these two forces and its direction measured clockwise from the horizontal.
Added by Robert T.
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The horizontal component of the force at A is F_A*cos(theta) and the vertical component is F_A*sin(theta). Similarly, for the force at B, the horizontal component is F_B*cos(theta) and the vertical component is F_B*sin(theta). Show more…
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