The point \( P \) with \( x \)-coordinate \( \frac{1}{2} \) lies on the curve with equation \( y=2 x^{2} \). The normal to the curve at \( P \) intersects the curve at points \( P \) and \( Q \). Find the coordinates of \( Q \). 62
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Given \( x = \frac{1}{2} \) and the curve equation \( y = 2x^2 \): \[ y = 2 \left( \frac{1}{2} \right)^2 = 2 \left( \frac{1}{4} \right) = \frac{1}{2} \] So, the coordinates of \( P \) are \( \left( \frac{1}{2}, \frac{1}{2} \right) \). Show more…
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