The polar form of the complex number $\frac{(11\angle 60^\circ)(35\angle -45^\circ)}{(2+3j)-(5+j)}$ is $\boxed{\phantom{000}} \angle \boxed{\phantom{000}}^\circ$.
Added by John J.
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$2+3j$ is already in rectangular form. $5+j$ is already in rectangular form. So, $(2+3j)-(5+j) = (2-5) + (3-1)j = -3+2j$. Show more…
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