Question

The pooled variance $sp^2$ is formed by combining information from two independent samples. If $s1^2 = 39$, $s2^2 = 25$, and $n1 = n2 = 12$ then $sp^2$ is equal to: Oa. 30 Ob. 45 Oc. 32 Od. 31

          The pooled variance $sp^2$ is formed by combining information from two independent samples. If $s1^2 = 39$, $s2^2 = 25$, and $n1 = n2 = 12$ then $sp^2$ is equal to:

Oa. 30
Ob. 45
Oc. 32
Od. 31
        
The pooled variance sp^2 is formed by combining information from two independent samples. If s1^2 = 39, s2^2 = 25, and n1 = n2 = 12 then sp^2 is equal to:

Oa. 30
Ob. 45
Oc. 32
Od. 31

Added by Mary F.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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The pooled variance sp^2 is formed by combining information from two independent samples. If s1^2 = 39, s2^2 = 25, and n1 = n2 = 12 then sp^2 is equal to: O a. 30 O b. 45 0 C. 32 O d. 31
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Transcript

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00:01 Hello students, given n1 is equal to 25, n2 is equal to 31, then degree of freedom of 1 is equal to n1 minus 1 that is 24 and degree of freedom of 2 is equal to n2 minus 1 that is 30.
00:24 Then given variants are sigma 1 square is equal to 10 and sigma 2 square is equal to 15.
00:34 Then probability that s1 square divided by s2 square greater than 1 .26 is equal to probability that f greater than s1 square divided by sigma 1 square divided by s2 square divided by sigma 2 square.
00:57 So, that is equal to probability that f greater than s1 square divided by s2 square into sigma 1 square sigma 2 square divided by sigma 1 square.
01:15 That is equal to probability that f greater than 1 .26 into 15 divided by 10.
01:22 That is equal to probability that f greater than 1 .89.
01:26 So, from the f normal table this value is 0 .0496.
01:43 That is f with 24 and 30 degree of freedom with 1 .89.
01:56 Now part b given n1 is equal to 8 and n2 is equal to 12...
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