The position of a simple harmonic oscillator is given by x(t) = 2 cos (/6 t) in (m) where t is in seconds. What is the maximum acceleration of the oscillator? 1. 7.3 m/s^2 2. 2.34 m/2^2 3. 0.54 m/s^2 4. 1.5 m/s^2
Added by Angela P.
Step 1
In this case, the position function is x(t) = 2 cos(π/6 t). To find the maximum acceleration, we need to take the second derivative of the position function with respect to time. Show more…
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