The position of the particle is given by s = (2t^2 - 8t + 6) m, where t is in seconds. Determine the time when the velocity of the particle is zero, and the total distance traveled by the particle when t = 3 s.
Added by Kenneth L.
Step 1
v(t) = \frac{d}{dt}(2t^2 - 8t + 6) Now, let's find the derivative. v(t) = 4t - 8 Show more…
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