00:01
So for this question, we have this position time graph in figure 3 .8 here.
00:07
And it says it represents the motion of a basketball coach during the last 8 seconds of the game in overtime.
00:14
We need to, for part 8, find the average velocity in the time intervals, naught to 2 seconds.
00:20
Well, from 0 .2 seconds, this is a displacement time graph.
00:26
So in a displacement time graph, oops, displacement time graph.
00:36
Our gradient is the velocity.
00:41
So therefore we're just looking for the gradient between 0 and 2 seconds, which is just distance over time, 10 divided by 2, which is 5 meters per second.
00:54
And then it wants in the region of 0 to 4 seconds.
00:58
In that time, his average velocity is, well, he travelled 5 meters, or he ended up 5 meters, his displacement was 5 meters, and it was for four seconds.
01:08
So that's 1 .25 meters per second.
01:13
Between 2 and 4, it's going to be from 10 to 5, but this time it's negative 5.
01:22
So negative 5 over 2, that's minus 2 .5 meters per second.
01:27
For 4, it is 4 to 7 seconds, so it's from 4 to 7 here.
01:34
So he starts at 5 meters and ends up at minus, i believe that's minus 5 meters.
01:42
So he travels minus 10 meters in a space of three seconds.
01:48
So that's going to be equal to minus 3 .3 meters per second.
01:55
And then finally, part v, nought to 8 seconds.
02:00
Well, he starts at zero and ends at zero.
02:03
So his average velocity is going to be zero.
02:06
And then divide by 8 is just going to be 0 meters per second...