00:01
So, according to the question, there is a circuit like this.
00:04
So let us suppose this is emf e and this is internal resistance r.
00:11
And here it is point b and here it is point a.
00:15
So, first of all, we have been given that if there is a current from negative terminal to positive terminal and the current value is i.
00:28
So i is equal to 1 .50 ampere.
00:32
And in this case, the potential difference va -vb is equal to 8 .40 volt.
00:41
So now if we apply the kirchhoff's law from point a to point b, if we go, so va and we can see that there is a negative terminal here and positive terminal here.
00:56
So we use the after sign always.
00:58
So it will be minus e.
01:00
So current is flowing from here to here.
01:02
So plus and this will be minus.
01:03
So we'll use the after sign.
01:05
So this will be plus i multiplied by r.
01:08
So 1 .50 multiplied by r.
01:11
Okay.
01:11
And this will be equal to vb.
01:13
So if we find the value here, it will be va.
01:16
Okay.
01:16
It is not vb.
01:17
It will be va here.
01:19
So va -vb will be equal to e -1 .50 r.
01:25
Okay.
01:25
So this will be our equation first.
01:27
And in the second case, we have been given that if it is the point a and here it is battery as cell.
01:35
And this is point b.
01:38
This is internal resistance r.
01:40
Okay.
01:41
And this time the current is flowing opposite of the previous direction.
01:44
Okay...