Question

The power consumption in thousands of kilowatt-hours of a home is described by the function ?(?) = 8?3 − 3?2, where ? is in months. Calculate the average consumption on the interval 2 ≤ ? ≤ 8. (That is from February to August)

          The power consumption in thousands of kilowatt-hours of a home is described by the function ?(?) = 8?3 − 3?2, where ? is in months. Calculate the average consumption on the interval 2 ≤ ? ≤ 8. (That is from February to August)
        

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Finite Mathematics and Calculus with Applications
Finite Mathematics and Calculus with Applications
Margaret L. Lial, Raymond N. Greenwell,… 9th Edition
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The power consumption in thousands of kilowatt-hours of a home is described by the function ?(?) = 8?3 − 3?2, where ? is in months. Calculate the average consumption on the interval 2 ≤ ? ≤ 8. (That is from February to August)
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Transcript

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00:01 So in this question we're told that the mean for electrical consumption is 2117 kilowatt hours and the standard deviation is 521 kilowatt hours.
00:14 Now the rule of thumb is that usual consumption is within two standard deviations of the mean.
00:34 So that means that the minimum usual amount is the mean minus two standard deviations.
00:46 So that's 2417 minus two times 521, which is 1 ,375 kilowatt hours.
00:57 And the maximum usual consumption is the mean plus two standard deviations...
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